108°

bissectrice de l'angle

bissectrice
de l'angle

médiatrice du
segment AB

cercle de centre O
et de 3 cm de rayon

Distances

AE = BE car E appartient 
à la médiatrice de AB.

Réponse :

A = Point(xAxis)
B = (5.254278593751456, 3.6660671152539064)
C = (13.505903672411751, 7.552249128309829)
E_1 = Point(xAxis)
D = (6.4836873807235715, 7.552249128309829)
F = (-5.895860558264587, 7.237577079256968)
a = Segment(B, C)
b = 0 (slider from 0 to 9, step 1)
G = Point(a)
c = OrthogonalLine(G, a)
d_1 = Circle(G, 3)
H = Intersect(d_1, c, 1)
d = Line(H, a)
f = Segment(H, G)
α = Angle(B, G, H)
β = Angle(B, D, C)
e = Ray(D, B)
g = Ray(D, C)
I = Point(e)
J = Point(g)
h = Segment(I, D)
i = Segment(D, J)
K = (5.5505209900920365, 5.853091406457445)
L = (8.436491124941748, 7.9980692093862835)
k = CircleArc(D, K, L)
M = Intersect(k, h, 1)
N = Intersect(k, i, 1)
p = Circle(M, 3)
q = Circle(N, 3)
O = Point(p)
P = Point(q)
Q = (8.74848789627685, 5.248597661995681)
r = CircleArc(M, O, Q)
R = (9.547979622823055, 4.683103513950805)
s = CircleArc(N, P, R)
S = Intersect(r, s, 1)
j = Ray(D, S)
t = Circle(B, 5)
c_1 = Circle(C, 5)
T = Point(t)
U = Point(t)
V = Point(c_1)
W = Point(c_1)
e_1 = CircleArc(B, U, T)
f_1 = CircleArc(C, W, V)
Z = Intersect(e_1, f_1, 1)
A_1 = Intersect(e_1, f_1, 2)
l = Line(Z, A_1)
g_1 = Circle(D, 3)
E = Intersect(d, l)
B_1 = (-5.876360760056143, 5.736092617206781)
m = false
C_1 = Point(l)
n = Segment(B, C_1)
a_1 = Segment(C_1, C)
o = false