Ex 6. Quelle allure? - b)
Author: Frédéric Chanez

NLR est un triangle équilatéral de 8 cm de côté.

Oui, car comme M est sur c, OM = 4 cm.

O = (0, -2)
a = 8 (slider from 0 to 8, step 1)
c = Circle(O, 4)
M = Point(c)
d = Circle(M, 4)
N = Intersect(c, d, 1)
P = Intersect(c, d, 2)
e = Circle(N, 4)
f = Circle(P, 4)
L = Intersect(d, f, 1)
R = Intersect(c, f, 2)
poly1, n, r, l = Polygon(R, L, N)
A = (10, 6)
B = (10, 0)
C = (10.601368045589846, 0.021947235497462806)
D = (10.628467591539264, -5.994151965273343)
E = (12.254440348504346, 0.6181372463846597)
F = (12.281539894453765, -0.3032473158955537)
G = (20.27590594953209, -0.27614776994613566)
H = (20.27590594953209, 0.6452367923340778)
poly2, e_1, f_1, g, h = Polygon(E, F, G, H)
I = Point(c)
b = Segment(O, I)
J = Point(d)
i = Segment(M, J)